Double Harmonized Form One Selection Formula
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A parameter called Adjusted Performance (AP) be introduced. This parameter is a function of 3 variables. They are Pupil's Total Marks; School Type Average ; Examination Center Average .
The school type average STA is the average of all the pupils total marks, countrywide, for that school type. The STA is either public schools average or private schools average .
In 2015, private schools average was 230.14 marks while public schools average was 180.87 marks. Top public school pupil scored 446 marks while top private pupil got 449 marks.
Every examination center will have its average of all pupils total marks calculated. This average is the Examination Center Average (ECA).
This suggested formula will prevent any given School Type or Examination Center from hogging most of the slots in the best top high schools.
Adjusted Performance
AP=S*T^2/(S*T+R)
where
AP=Adjusted Performance
T=Pupil's Total Marks
R=STA multiplied by ECA
S=STA + ECA
Alternatively
Adjusted Performance (AP) = T - Z
where T = Pupil's Total Marks
while Z = T//STA//ECA and is read as T parallel ECA parallel STA
example 1
calculate Z and AP for Total marks 450; STA 300; ECA 250
solution
Z=450//300//250
1/Z=1/450 + 1/300 + 1/250 =0.00955555555
Z = 104.651163
AP=T-Z=450-104.65=345.35
This formula attempts to harmonize a pupil's KCPE exam total marks irrespective of the school type, either public or private. The higher the pupil's total marks, the higher the Adjusted Performance (AP). Both the School type Average (STA) and Examination Center Average (ECA) cause adjustment to the AP, hence the double harmonization.
After harmonization, the AP can then be used for Form one selection. While using the AP, every pupil is fair game and there is no need for those contentious private and public school quotas, The AP is the only determinant,
The result slip should indicate both the pupil's total marks and the calculated Adjusted Performance.
worked examples
marks 449; STA 230.14; ECA 400 gives 338.78 AP
marks 446; STA 230.14; ECA 400 gives 335.96 AP
marks 446; STA 180.87; ECA 400 gives 348.64 AP
marks 420; STA 230.14; ECA 400 gives 311.61 AP
marks 420; STA 230.14; ECA 114 gives 355.48 AP
marks 420; STA 180.87; ECA 400 gives 323.94 AP
marks 420; STA 180.87; ECA 114 gives 360.05 AP
marks 300; STA 230.14; ECA 250 gives 214.37 AP
marks 300; STA 230.14; ECA 200 gives 221.13 AP
marks 300; STA 180.87; ECA 250 gives 222.25 AP
marks 300; STA 180.87; ECA 200 gives 227.86 AP
marks 200; STA 230.14; ECA 150 gives 137.55 AP
marks 200; STA 230.14; ECA 100 gives 148.31 AP
marks 200; STA 180.87; ECA 150 gives 141.85 AP
marks 200; STA 180.87; ECA 100 gives 151.29 AP
marks 500; STA 230.14; ECA 500 gives 380.17 AP
marks 500; STA 180.87; ECA 500 gives 395.06 AP
marks 500; STA 500; ECA 500 gives 333.33 AP
The maximum obtainable AP equals the pupil's total marks when the STA equals Zero or ECA equals Zero.
The pupil thus competes with himself or herself and their School Type Average and Examination Center Average. The higher the pupil's total marks in conjunction with the "scatter", the higher the AP. Scatter is the difference between Pupil's Total Marks and STA. Also the difference between Pupil's Total Marks and ECA is scatter.
Example 2
Abdi, a pupil from a public school in Mandera scored 420 marks in 2015. His examination center had an average of 114 marks. Calculate Z and AP.
Solution
AP=T-Z
Z=420//180.87//114
1/Z=1/420+1/180.87+1/114=0.016682
Z=59.95
AP=T-Z=420-59.95=360.05
Using this AP method, Abdi is the Top KCPE pupil in 2015 !!!
Some of life's problems and challenges have very simple solutions e.g the wheel, fire, penicillin etc