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4lourBliss
#1 Posted : Sunday, November 03, 2013 11:24:40 AM
Rank: Member


Joined: 5/9/2013
Posts: 285
Location: hapakule.
in my farm, i keep chickens and goats, the total head count for both is 19 and the total number of their legs is 60. How many chickens and goats are there in farm?
Whatever the mind of man can conceive and believe, it can achieve.
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4lourBliss
#2 Posted : Sunday, November 03, 2013 11:27:38 AM
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Joined: 5/9/2013
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Location: hapakule.
Take away my first letter, and I still sound the same. Take away my last letter, I still sound the same. Even take away my letter in the middle, I will still sound the same. I am a five letter word. What am I?
Whatever the mind of man can conceive and believe, it can achieve.
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kysse
#3 Posted : Sunday, November 03, 2013 11:44:17 AM
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Joined: 1/17/2013
Posts: 4,693
Location: Earth
19

1 head= 2 or 4 legs.
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4lourBliss
#4 Posted : Sunday, November 03, 2013 11:47:14 AM
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Joined: 5/9/2013
Posts: 285
Location: hapakule.
kysse wrote:
19

1 head= 2 or 4 legs.



Shame on you Shame on you nope
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4lourBliss
#5 Posted : Sunday, November 03, 2013 11:55:19 AM
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Joined: 5/9/2013
Posts: 285
Location: hapakule.
Johnny’s mother had three children. The first child was named April. The second child was named May. What was the third child’s name?
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carygoh
#6 Posted : Sunday, November 03, 2013 11:58:47 AM
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Posts: 1,703
4lourBliss wrote:
Johnny’s mother had three children. The first child was named April. The second child was named May. What was the third child’s name?


Johnny
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jaggernaut
#7 Posted : Sunday, November 03, 2013 11:58:59 AM
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Joined: 10/9/2008
Posts: 5,389
4lourBliss wrote:
in my farm, i keep chickens and goats, the total head count for both is 19 and the total number of their legs is 60. How many chickens and goats are there in farm?


Simple...

let chicken = x
and goats = y

Then just solve the equation..

x + y = 19 (based on heads)
2x + 4y = 60 (based on legs)

Thus
x=19-y

therefore
2(19-y)+4y=60
38-2y+4y=60
2y=22
y=11

Thus x=8

Therefore: chicken are 8 with 16 legs
goats are 11 with 44 legs.

Total 19 heads and 60 legs.

**unless you are including the '5th leg' of the billy goatssmile
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washiku
#8 Posted : Sunday, November 03, 2013 11:59:25 AM
Rank: Chief


Joined: 5/9/2007
Posts: 13,095
4lourBliss wrote:
Johnny’s mother had three children. The first child was named April. The second child was named May. What was the third child’s name?


Johnnysmile
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washiku
#9 Posted : Sunday, November 03, 2013 12:01:09 PM
Rank: Chief


Joined: 5/9/2007
Posts: 13,095
jaggernaut wrote:
4lourBliss wrote:
in my farm, i keep chickens and goats, the total head count for both is 19 and the total number of their legs is 60. How many chickens and goats are there in farm?


Simple...

let chicken = x
and goats = y

Then just solve the equation..

x + y = 19 (based on heads)
2x + 4y = 60 (based on legs)

Thus
x=19-y

therefore
2(19-y)+4y=60
38-2y+4y=60
2y=22
y=11

Thus x=8

Therefore: chicken are 8 with 16 legs
goats are 11 with 44 legs.

Total 19 heads and 60 legs.


Ditto
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4lourBliss
#10 Posted : Sunday, November 03, 2013 12:02:07 PM
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Joined: 5/9/2013
Posts: 285
Location: hapakule.
carygoh wrote:
4lourBliss wrote:
Johnny’s mother had three children. The first child was named April. The second child was named May. What was the third child’s name?


Johnny


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kysse
#11 Posted : Sunday, November 03, 2013 12:04:22 PM
Rank: Elder


Joined: 1/17/2013
Posts: 4,693
Location: Earth
jaggernaut wrote:
4lourBliss wrote:
in my farm, i keep chickens and goats, the total head count for both is 19 and the total number of their legs is 60. How many chickens and goats are there in farm?


Simple...

let chicken = x
and goats = y

Then just solve the equation..

x + y = 19 (based on heads)
2x + 4y = 60 (based on legs)

Thus
x=19-y

therefore
2(19-y)+4y=60
38-2y+4y=60
2y=22
y=11

Thus x=8

Therefore: chicken are 8 with 16 legs
goats are 11 with 44 legs.

Total 19 heads and 60 legs.

**unless you are including the '5th leg' of the billy goatssmile


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4lourBliss
#12 Posted : Sunday, November 03, 2013 12:04:51 PM
Rank: Member


Joined: 5/9/2013
Posts: 285
Location: hapakule.
washiku wrote:
jaggernaut wrote:
4lourBliss wrote:
in my farm, i keep chickens and goats, the total head count for both is 19 and the total number of their legs is 60. How many chickens and goats are there in farm?


Simple...

let chicken = x
and goats = y

Then just solve the equation..

x + y = 19 (based on heads)
2x + 4y = 60 (based on legs)

Thus
x=19-y

therefore
2(19-y)+4y=60


smile Applause Applause
38-2y+4y=60
2y=22
y=11

Thus x=8

Therefore: chicken are 8 with 16 legs
goats are 11 with 44 legs.

Total 19 heads and 60 legs.


Ditto


smile smile Applause Applause
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jaggernaut
#13 Posted : Sunday, November 03, 2013 12:08:48 PM
Rank: Elder


Joined: 10/9/2008
Posts: 5,389
4lourBliss wrote:
washiku wrote:
jaggernaut wrote:
4lourBliss wrote:
in my farm, i keep chickens and goats, the total head count for both is 19 and the total number of their legs is 60. How many chickens and goats are there in farm?


Simple...

let chicken = x
and goats = y

Then just solve the equation..

x + y = 19 (based on heads)
2x + 4y = 60 (based on legs)

Thus
x=19-y

therefore
2(19-y)+4y=60


smile Applause Applause
38-2y+4y=60
2y=22
y=11

Thus x=8

Therefore: chicken are 8 with 16 legs
goats are 11 with 44 legs.

Total 19 heads and 60 legs.


Ditto


smile smile Applause Applause

Now you can see why I scored an A in mathematics.smile smile smile
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4lourBliss
#14 Posted : Sunday, November 03, 2013 12:10:04 PM
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Joined: 5/9/2013
Posts: 285
Location: hapakule.
Using only addition, how do you add eight 8’s and get the number 1000?
Whatever the mind of man can conceive and believe, it can achieve.
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Njung'e
#15 Posted : Sunday, November 03, 2013 12:10:49 PM
Rank: Elder


Joined: 2/7/2007
Posts: 11,935
Location: Nairobi
[quote=jaggernaut][quote=4lourBliss][quote=washiku][quote=jaggernaut][quote=4lourBliss]


You copied from my workSad smile smile
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4lourBliss
#16 Posted : Sunday, November 03, 2013 12:13:28 PM
Rank: Member


Joined: 5/9/2013
Posts: 285
Location: hapakule.
Sally is 54 years old and her mother is 80, how many years ago was Sally’s mother three times her age?
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kysse
#17 Posted : Sunday, November 03, 2013 12:18:36 PM
Rank: Elder


Joined: 1/17/2013
Posts: 4,693
Location: Earth
This thread reminds me of the BODMAS one.Laughing out loudly
jagger leta jibu.
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Njung'e
#18 Posted : Sunday, November 03, 2013 12:23:11 PM
Rank: Elder


Joined: 2/7/2007
Posts: 11,935
Location: Nairobi
kysse wrote:
This thread reminds me of the BODMAS one.Laughing out loudly
jagger leta jibu.


Looks like you used to go to school on Sundays alone.smile
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Mastermind
#19 Posted : Sunday, November 03, 2013 12:24:20 PM
Rank: Veteran


Joined: 1/25/2012
Posts: 1,624
Location: Langley
4lourBliss wrote:
Using only addition, how do you add eight 8’s and get the number 1000?

888+88+8+8+8= 1000











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sumuni
#20 Posted : Sunday, November 03, 2013 12:24:49 PM
Rank: Member


Joined: 6/24/2007
Posts: 111
Location: Afrique
4lourBliss wrote:
Sally is 54 years old and her mother is 80, how many years ago was Sally’s mother three times her age?

41 years ago.
Solution;
Let the no. of years ago when sally mother's age was 3 times hers be Y
Then
3(54-Y) = (80-Y)
162-3Y = 80 - Y
Putting like terms together,
162-80 = 3Y-Y
82 = 2Y
Hence,
Y = 41
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